[Support request] Display rules for elements : regex possible?

[Maxime]

Hi,

I would like to use the elements to display a different header image depending the directory of my pages.

Example :

https://mywebsite.com/directory1/page-1
https://mywebsite.com/directory1/page-2
https://mywebsite.com/directory1/page-3

>> The same element for all the directory /directory1/

https://mywebsite.com/directory2/page-a
https://mywebsite.com/directory2/page-b
https://mywebsite.com/directory2/page-c

>> The same element for all the directory /directory2/

Curently in the display rules I chose “page” and pick each page one-by-one (I have hundreds)

>> Is it possible to use a regex that with my directory name?

Thank you for your help

[Leo]

Hi there,

You can use this filter for advanced display rules:
https://docs.generatepress.com/article/generate_element_display/

You will need to find the correct conditional tag to use which is not related to the theme:
https://codex.wordpress.org/Conditional_Tags

Hope this helps 🙂

[Maxime]

Hi Leo,

Thank you, this solution seems to answer my need, but but it doesn’t work. Did I misunderstand something?

At the end of the function.php file in my child theme I added :

add_filter( 'generate_element_display', function( $display, $element_id ) {
    global $post;

    if ( 5281 === $element_id && ( is_page() && $post->post_parent == '3854' ) ) {
        $display = true;
    }

    return $display;
}, 10, 2 );

5281 : My Element ID
3854 : My parent page ID (/directory1/ in my previous example)

Thank you in advance

[David]

Hi there,

what happens if you flip it on its head, and set the Element Display rules to display on ALL pages, and set a negative condition to make it false:

if ( 5281 === $element_id && !( is_page() && $post->post_parent == '3854' ) ) {
    $display = false;
}

[Maxime]

Hi David,

I tried :
– I chose “All website” as display rule
– I set a negative condition :

add_filter( 'generate_element_display', function( $display, $element_id ) {
    global $post;

if ( 5281 === $element_id && !( is_page() && $post->post_parent == '3854' ) ) {
    $display = false;
}

    return $display;
}, 10, 2 );

>> The function don’t working because my header is displayed on all pages
Screenshot with my function (sorry back-office in french) : https://ibb.co/6bfZx5C

[Ying]

Hi Maxime,

When using this PHP snippet, can you make sure the location of the element is set to blank?

add_filter( 'generate_element_display', function( $display, $element_id ) {
    global $post;

    if ( 5281 === $element_id && ( is_page() && $post->post_parent == '3854' ) ) {
        $display = true;
    }

    return $display;
}, 10, 2 );

Check the screenshot below:
https://www.screencast.com/t/RGtiPYHp

[Maxime]

Hi Ying,

Yes I tried to setting empty or pick other elements (all websites, pages…). but nothing change.

[David]

I tested Yings latest version, with the Block Elements display rules set to ‘blank’ and it worked.

Can you double check the ID of the Element and the Post Parent ?

[Maxime]

I double checked The IDs and I tried with another page and another element(with the corresponding IDs), but no change.

When I Publish/Update my element, I have the followgin message : https://ibb.co/C11Sgbb
Could this be an indication regarding this issue?

[Ying]

Ah I see, header element doesn’t allow publish without location.

Can you try using block element?

[Maxime]

I tried with a “block” type Element but it still doesn’t work : https://ibb.co/GsdrBND

if it’s easier for you, I can give you a temporary access to the website. Let me know.

[David]

Send us a temporary admin login and we can take a look.
You can share the login details in the Private Information field.

[Maxime]

Thank you, I shared the access

[David]

Ok – first thing i notice is the GP Premium version is only 1.12 – which is really out of data and the generate_element_display filter wasn’t added until version 2.0.

Is it possible to update the plugin ?

[Maxime]

Oh yes,I updated the plugin with the version 2.1.2

[Author]

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